Алгебраические формулы
Вопросы - Математика и статистика
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cos=1-sin2=(1-tg2/2)/(1+tg2/2)sin=1/1+ctg2=(2tg/2)/(1+tg2/2)cos()=sinsincoscossin(=sincossincostg(+)=sin(+)/cos(+)=(tg+tg)/(1-tgtg)tg(-)=(tg-tg)/(1+tgtg)ctg(+)=(ctgctg-1)/(ctg+ctg)ctg(-)=(ctgctg+1)/(ctg-ctg)sin2=2sincos=(2tg)/(1+tg2)cos2=cos2-sin2=(1-tg2)/(1+tg2)=2cos2-1=1-2sin2tg2=2tg/(1-tg2)ctg2=(ctg2-1)/2ctgctg2=(ctg2-1)/2ctg cos2/2=1+cos/2cos2=(1+cos2)/2sin2/2=1-cos/2sin2=(1-cos2)/2cos/2=1+cos/2sin/2=1-cos/2tg/2=1-cos/1+cos=(sin)/(1+cos)=(1-cos)/sinctg/2=1+cos/1-cos=sin/(1-cos)=(1+cos)/sinsin+cos=2 cos(/4-)sin-cos=2 sin(-/4)cos-sin=2 sin(/4-)cos+cos=2cos(+)/2cos(-)/2cos-cos=-2sin(+)/2sin(-)/2sin+sin=2sin(+)/2cos(-)/2sin-sin=2sin(-)/2cos(+)/2tgtg=(sin())/coscoscoscos=1/2(cos()+cos(+))sinsin=1/2(cos()-cos(+))sincos=1/2(sin(+)+sin(-))tg=(2tg/2)/(1-tg2/2)
cos=1-sin2=(1-tg2/2)/(1+tg2/2)sin=1/1+ctg2=(2tg/2)/(1+tg2/2)cos()=sinsincoscossin(=sincossincostg(+)=sin(+)/cos(+)=(tg+tg)/(1-tgtg)tg(-)=(tg-tg)/(1+tgtg)ctg(+)=(ctgctg-1)/(ctg+ctg)ctg(-)=(ctgctg+1)/(ctg-ctg)sin2=2sincos=(2tg)/(1+tg2)cos2=cos2-sin2=(1-tg2)/(1+tg2)=2cos2-1=1-2sin2tg2=2tg/(1-tg2)ctg2=(ctg2-1)/2ctgctg2=(ctg2-1)/2ctg cos2/2=1+cos/2cos2=(1+cos2)/2sin2/2=1-cos/2sin2=(1-cos2)/2cos/2=1+cos/2sin/2=1-cos/2tg/2=1-cos/1+cos=(sin)/(1+cos)=(1-cos)/sinctg/2=1+cos/1-cos=sin/(1-cos)=(1+cos)/sinsin+cos=2 cos(/4-)sin-cos=2 sin(-/4)cos-sin=2 sin(/4-)cos+cos=2cos(+)/2cos(-)/2cos-cos=-2sin(+)/2sin(-)/2sin+sin=2sin(+)/2cos(-)/2sin-sin=2sin(-)/2cos(+)/2tgtg=(sin())/coscoscoscos=1/2(cos()+cos(+))sinsin=1/2(cos()-cos(+))sincos=1/2(sin(+)+sin(-))tg=(2tg/2)/(1-tg2/2)