Измерение магнитострикции ферромагнетика с помощью тензодатчика

Реферат - Физика

(?l/l)0 = e(0)xx ?21+ e(0)yy ?22+ e(0)zz ?23+ e(0)xy ?1 ?2+ e(0)yz ?2 ?3+ e(0)zx ?3?1=

= - [B1/(C11-C12)] [21 ?21+22 ?22+23 ?23- 1/3]

(B2/C44)( 12 ?1 ?2+23 ?2 ?3+31 ?3 ?1) (17)

?l/l [100] [III]. [100], , (17)

1 = ?1 = 1, 2 = 3 = ?2 = ?3 = 0,

(?l/l)[100] =?100 = - 2/3 [B1/(C11-C12)]. (18)

[111]

(?l/l)[111] =?111 = - 1/3 (B2/C44) , (19)

?100 ?111 .
(18,19), :

B1=N(?g1/?r)r0 , B2= 2Ng1, (20)

- N .
?100 ?111 g1 :

?100 = -2/3[N/(C11 C12)][?g1/?r]r0 ;

?111 = - 4/3(N/C44)g1

2- - :

?100 = -16/9[N/(C11 C12)]g1 ; (21)

?111 = - 16/27[g1+(?g1/?r)r0]

3 :

?100 = -1/3[N/(C11 C12)][6g1 (?g1/?r)r0] ;

?111 = - 2/3[N/C44] [2g1+(?g1/?r) r0]

(16), (13) (12) :

f(0).= [B21/(C11 C12)] ? (2i-1/3)2 - B22/C44 ? 2i2j , (i , j=1,2,3)

f(0).= C11 [B21/(C11 C12)2] ? (2i-1/3)2 + C44 B22? 2i2j+

+C12[B21/(C11 C12)2] ? (2i-1/3)(2j-1/3), (i , j=1,2,3)

1) ?2 i =1 (i =1,2,3) ;

2) ?4 i =1 2 ? 2 i 2j (i , j=1,2,3) ;

3) ? (2i-1/3)2= 2/3 2 ? 2i2j (i , j=1,2,3, i>j) ;

4) ? (2i-1/3)(2j-1/3) = ? 2i2j 1/3 (i , j=1,2,3, i>j) ;

f(0).= [B21/(C11 C12)][ 2/3 2 ? 2i2j] - B22/C44 ? 2i2j ,

(i , j=1,2,3, i>j) (22)

f(0).= C11 [B21/(C11 C12)2] [ 2/3 2 ? 2i2j] + C44 B22? 2i2j+

+C12[B21/(C11 C12)2] ? 2i2j 1/3 ,

(i , j=1,2,3,i>j) (23)

(21) (23) (1) (10), (18) (19), :

f =(K1+?K1)? 2i2j (i , j=1,2,3, i>j) (24)

?K1